0.125x^2-10x+200=0

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Solution for 0.125x^2-10x+200=0 equation: 



0.125x^2-10x+200=0

a = 0.125; b = -10; c = +200;
Δ = b2-4ac
Δ = -102-4·0.125·200
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{10}{0.25}=40$

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